Permutation ( Definition, Formula, Types, and Examples)

SOLVED: Find the number of distinguishable permutations of the given letters AAABBBCC. There are 9!/(3! * 3! * 2!) = 1680 permutations.If a permutation is chosen at random, what is the probability that it begins with at least 2 A's? The probability is P = (6!/(3! * 3! * 2!))/(9!/(3! * 3! * 2!)) = 1/3.

Permutation | Definition & Examples

Distinguishable Permutation Part 2 #reels #fbreels #teacher #math #fyp #reelsinstagram #fb #fypシ゚viralシ #teachersofinstagram #fypシ゚ | Moises Carlos